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Does Vmax change?

Thus, the amount of enzyme becomes the rate-controlling parameter, and an increase in the enzymes increases the maximal velocity or Vmax. Therefore, the higher the enzyme amount, the higher the Vmax of the reaction.
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Does Vmax always stay the same?

Vmax is maximum for a particular enzyme in a defined set of conditions. You cannot increase it further, it is the maximum. That is the last part of your question. So, for a particular Vmax the Km is always the same.
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Does Vmax change with concentration?

The Vmax does not depend on the concentration of substrate. As the rate of reaction increases when the concentration of substrate increases initially. After a certain time, the rate of the reaction reaches its maximum value Vmax and there is no further change in the rate with substrate concentration.
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Does Vmax increase as km increases?

With the increase in substrate concentration, Vmax can be achieved. So, Vmax remains the same but KM increases because the reaction is able to reach half of its Vmax at an increased substrate concentration.
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What does Vmax depend on?

The rate of reaction when the enzyme is saturated with substrate is the maximum rate of reaction, Vmax. The relationship between rate of reaction and concentration of substrate depends on the affinity of the enzyme for its substrate.
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This is why Yamaha VMax SUCKS

Why does Vmax change?

In non-competitive inhibition, the inhibitor molecules do not compete with the substrates for active sites on the enzyme surface, but some other site on the enzyme. This results in a decrease in the enzyme molecules that can catalyse the reaction. Hence, Vmax is lowered.
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What causes Vmax to decrease?

Inactivation of the enzyme decreases the maximum rate of the reaction (Vmax), defined as the rate of the reaction at a substrate concentration that fully saturates all active sites of the specific enzyme.
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Does lower Km mean higher Vmax?

The value of KM is inversely related to the affinity of the enzyme for its substrate. High values of KM correspond to low enzyme affinity for substrate (it takes more substrate to get to Vmax ). Low KM values for an enzyme correspond to high affinity for substrate.
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Does Km decrease if Vmax decreases?

Typically, in competitive inhibition, Vmax remains the same while Km increases, and in non-competitive inhibition, Vmax decreases while Km remains the same. The change in both of these variables is another finding consistent with the effects of a mixed inhibitor.
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Why Vmax is unchanged in competitive inhibition?

Competitive inhibitors compete with the substrate at the active site, and therefore increase Km (the Michaelis-Menten constant). However, Vmax is unchanged because, with enough substrate concentration, the reaction can still complete.
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Does Vmax increase when pH increases?

A) The maximum rate or Vmax of an enzyme-catalyzed reaction depends on the pH (potential of hydrogen). Enzymes remain active at an optimum pH and an increase or decrease in pH from the optimum level, causes the Vmax to decrease. Thus, an increase in pH causes the Vmax to decrease, not increase.
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Does Vmax increase with more substrate?

Maximal Velocity (Vmax): Increasing the substrate concentration indefinitely does not increase the rate of an enzyme-catalyzed reaction beyond a certain point. This point is reached when there are enough substrate molecules to completely fill (saturate) the enzyme's active sites.
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Is Vmax always higher than KM?

For the competitive inhibitor, Vmax is the same as for the normal enzyme, but Km is larger. For the noncompetitive inhibitor, Vmax is lower than for the normal enzyme, but Km is the same.
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Does Vmax decrease?

As you can see, Vmax is reduced in non-competitive inhibition compared to uninhibited reactions. This makes sense if we remember that Vmax is dependent on the amount of enzyme present. Reducing the amount of enzyme present reduces Vmax.
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What reduces Vmax but does not alter Km?

Non-competitive inhibition:

It can bind to both the enzyme and enzyme-substrate complex. Increasing the substrate will not overcome the inhibition, hence, Vmax decreases and hence, Km remains same.
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Does Km and vmax change in uncompetitive inhibition?

Uncompetitive inhibitors decrease Vmax and KM to the same extent.
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What is the effect on Vmax and Km?

Vmax is the reaction rate at the state where the enzyme is fully saturated by the substrate. The key difference between Km and Vmax is that Km measures how easily the enzyme can be saturated by the substrate, whereas Vmax is the maximum rate at which an enzyme is catalyzed when the enzyme is saturated by the substrate.
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What do you interpret from Km and Vmax values?

Vmax is the maximum reaction velocity at which all enzymes become saturated with substrate. Km is the substrate concentration at which half of the maximum velocity is achieved.
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Does Vmax change with inhibition?

Vmax is the maximum velocity of the enzyme. Competitive inhibitors can only bind to E and not to ES. They increase Km by interfering with the binding of the substrate, but they do not affect Vmax because the inhibitor does not change the catalysis in ES because it cannot bind to ES.
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Can Vmax increase?

Vmax obviously increases when the enzyme concentration is changed because the amount of enzyme affects the rate of turnover given sufficient substrate.
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Does change of pH affect Vmax and KM?

Vmax/Km decreased above pH 6.8 because of ionization of a group required in the acid form in the free enzyme, with a pK of 7.88 at 30 degrees C and a delta H of about 13 kJ/mol.
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What factors increase Vmax?

Vmax value is influenced by three main factors, namely, enzyme concentration, temperature, and pH.
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Does Vmax depend on pH?

The maximal velocity of the reaction (or maximal rate) Vmax is the rate attained when the enzyme sites are saturated with substrate, i.e. when the substrate concentration is much higher than the KM. The Vmax value depends on environmental conditions, such as pH, temperature and ionic strength.
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Is Vmax affected by temperature?

In most cases, Km did not increase as fast as Vmax, consequently the enzyme efficiency, Vmax/Km, also increased slightly with temperature.
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