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How many 128 * 8 bit RAMs are required to design 32k * 32-bit RAM?

Total bits in desired RAM / Total bits in a single 128 × 8 bit RAM = (32768 × 32) / 1024 (32768 × 32) / 1024 = 1024 So, 1024 units of 128 × 8 bit RAMs are required to design a 32 K × 32 bit RAM.
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How many numbers of 256 8 bit RAMs are required to build 1kb 16 RAM?

Explanation: (1024 x 8)/(256 x 1 ) = 32.
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How many 128 8 RAM chips are needed to provide a memory capacity of 4096 bytes?

Expert-Verified Answer

Memory chips can hold memory either temporarily through random access memory or permanently through read only memory. The answer to the above question is 4096x16/128x8 o2r ^12x2^4/2^7x2^3 or 2^16/2^10 =2^6.
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What is 128 8 RAM?

A 128 * 8 RAM chip has a memory capacity of 128 words of eight bits (one byte) per word. This requires a 7-bit address and an 8-bit bidirectional data bus. The 8-bit bidirectional data bus allows the transfer of data either from memory to CPU during a read operation or from CPU to memory during a write operation.
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How many 256x8 RAM chips are needed to provide a memory capacity of 2048 bytes?

Hence 16 RAM chips are required.
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Q. 7.8: (a) How many 32K * 8 RAM chips are needed to provide a memory capacity of 256Kbytes? (b) How

How many 32K 1 RAM chips are needed to provide a memory capacity of 256?

How many 32K x 1 RAM chips are needed to provide a memory capacity of 256K-bytes? Explanation: We need 256 Kbytes, i.e., 256 x 1024 x 8 bits. We have RAM chips of capacity 32 Kbits = 32 x 1024 bits.
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How many chips of 8x4 are required for a total required memory of 32x8 bits?

Given that each chip has 8 bits of data input/output and that there is a 32-bit data bus, We need at least 4 chips (8 x 4)= 32 bits.
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How many 128 * 8 RAM chips are needed?

According to question,128 x 8 RAM = 1024 bitsand1 bit = 1/8ByteThus,1024 bits = 1024 /8= 128 Byte1 RAM chip = 128 ByteLets consider there are n number of Chips to provide 2048 BytesNow,1RAM Chip = 128 Byte128n = 2048n = 16Therefore, 16 Chips will be needed to provide memory capacity of2048 bytes. Answer 1.
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How many 256 * 8 memory chips are required to obtain a 2048 * 8 memory?

Hence the number of such RAM chips required, or 16 chips.
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How much RAM can a 128 bit system use?

Representation. A processor with 128-bit byte addressing could directly address up to 2128 (over 3.40×1038) bytes, which would greatly exceed the total data captured, created, or replicated on Earth as of 2018, which has been estimated to be around 33 zettabytes (over 274 bytes).
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How many memory chips are needed to build a 128kb memory system using only 32kb memory devices?

2 shows a 128 KB memory system built from two 32 KB and one 64KB memory chips and interfaced to the 8086 microprocessor.
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How do I calculate RAM chips?

Each chip contains 8 bits. Because it takes 8 bits to make 1 byte, the capacity of the module can be calculated by grouping the memory chips on the module into groups of eight. If each chip contains 512Mb, a group of eight means that the module has a size of 512MB (512Mb x 8 = 512MB).
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How to calculate RAM size?

How Much RAM Do I Have?
  1. Locate the Computer icon in the Start menu.
  2. Right-click the Computer icon and select Properties from the menu.
  3. Under System and beneath the processor model, you can see the installed memory amount, measured in MB (megabytes) or GB (gigabytes).
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How many address lines does a 32kb memory device have?

How many address lines are required by the memory that contains 32k words? 15 with a pure parallel address bus.
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How many 4k 8 ROM chips would be required to build a 64k 8 memory system?

YEs, you will need 32 chips.
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How many bits are required to store the number 256 is it 8 or 9?

One bit of information is so little that usually computer memory is organized into groups of eight bits. Each eight-bit group is called a byte. Because it has 8 bits, it can store or 256 different values.
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How many bytes are there in 32K * 4 memory chip?

How many bytes are there in a 32k*4 memory chip? Given the technical definition of a byte as the smallest addressable amount of memory , then there are 32K bytes.
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How many such rams will be required to construct 1 32 memory bank?

Answer: A total of 32 RAM chips are needed to build 1 MB of memory. = 32 chips. Thus, 32 RAM chips are needed to build 1 MB of memory.
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Can the number 256 be stored in an 8-bit number?

The maximum decimal number that can be represented with 1 byte is 255 or 11111111. An 8-bit word greatly restricts the range of numbers that can be accommodated. But this is usually overcome by using larger words. With 8 bits, the maximum number of values is 256 or 0 through 255.
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How many 128 16 RAM chips are needed?

Answer: 16K bytes = 16 x 1024 x 8 => 128 chips. 16 groups of 8 chips which have same address/chip select lines.
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How many chips of 512K * 8 are required for constructing 4m * 32 memory?

Expert Answer

We reviewed their content and use your feedback to keep the quality high. We know, 1M = 1024K So, number of memory chips required to make (8M x 32) using (512K x 8) is =(8 x 1024 x 32) / (512 x 8) = 64 2.
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How many 1024 * 2 RAM chips are required to construct a 1024 * 8 memory system?

Explanation: One 1024 * 1 RAM chips is of 1-bit. SO, for construction of 1024 * 8 RAM chip of 8-bits, it will require 8 chips.
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How much memory is in a 8 bit CPU?

8-bit CPUs use an 8-bit data bus and can therefore access 8 bits of data in a single machine instruction. The address bus is typically a double octet (16 bits) wide, due to practical and economical considerations. This implies a direct address space of 64 KB (65,536 bytes) on most 8-bit processors.
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How many RAM chips of size 256 K 1 bit are required to build 1 m byte memory?

No. of RAM chips=1MB/256K=1024x1024x8/256x1024 =32.
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How do I find the maximum RAM size?

Check Maximum RAM Capacity of Your Computer
  1. Have you ever thought about upgrading your PC RAM to larger capacity? ...
  2. Open Run by pressing Windows key + R. ...
  3. Copy the command – wmic memphysical get maxcapacity to the Command Prompt window and press Enter. ...
  4. The Last Step. ...
  5. 33554432KB / 1024 = 32768MB, 32768MB / 1024 = 32 GB.
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